9^x+2-3^2x-2=2(6/27)^2

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Solution for 9^x+2-3^2x-2=2(6/27)^2 equation: 



9^x+2-3^2x-2=2(6/27)^2

We move all terms to the left:

9^x+2-3^2x-2-(2(6/27)^2)=0

We add all the numbers together, and all the variables

9^x-3^2x+2-2-(2(+6/27)^2)=0

We add all the numbers together, and all the variables

9^x-3^2x-(2(+6/27)^2)=0

We multiply all the terms by the denominator


9^x*27)^2)-3^2x*27)^2)-(2(+6=0

Wy multiply elements

6561x^3=0

We do not support expression: x^3

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